Someone knows
why defining a strstream variable and using a popen() a SIGCHLD arrived ?
example:
…
…
stream problem(static_buf,2048);
…
…
void main(int argc, char **argv)
…
…
fd=popen(cmd,“r”);
while (!feof(fp))
{
fscanf(fp, “%s “, stringa);
// printf(”%s”,stringa);
}
…
…
during the while () loop a SIGCHLD arrived !!!.
(this is not true if you comment the strstream variable.)
Does someone know why ???
Thank’s in advance.
PRC-ASW <prcswdpt@tin.it> wrote:
Someone knows
why defining a strstream variable and using a popen() a SIGCHLD arrived ?
popen() creates a child process. If that child has died, then it is normal
for a SIGCHLD to get delivered to the parent.
I think the default behaviour for SIGCHLD is for it to be ignored, have
you modified your handling of SIGCHLD? Maybe C++ library for strstream
modifies it? I don’t know the internals of the C++ library well enough.
-David
example:
.
.
stream problem(static_buf,2048);
.
.
void main(int argc, char **argv)
.
.
fd=popen(cmd,“r”);
while (!feof(fp))
{
fscanf(fp, “%s “, stringa);
// printf(”%s”,stringa);
}
.
.during the while () loop a SIGCHLD arrived !!!.
(this is not true if you comment the strstream variable.)Does someone know why ???
Thank’s in advance.
–
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