I just ported from NTO6.0 to 6.1 and my code that was using typeid to
determine object types under 6.0 no longer works. It always evaluates to
false. Is this a known bug?
Ex.
std::string temp;
if(typeid(temp) == typeid(std::string))
{
}
Kevin Hykin <kevin.hykin@bepco.com> wrote:
I just ported from NTO6.0 to 6.1 and my code that was using typeid to
determine object types under 6.0 no longer works. It always evaluates to
false. Is this a known bug?std::string temp;
if(typeid(temp) == typeid(std::string))
{
}
I am unable to recreate that problem using your code example. I modified
it slightly so it would compile:
#include
using namespace std;
int main (int argc, char* argv[])
{
string temp;
if (typeid(temp) == typeid(string))
{
cout << “Works!” << endl;
}
return 0;
}
The if statement evaluates to true, and “Works” is put to the iostream. Do
you have a test case that can illustrate the problem you’re having?
-Adam
amallory@qnx.com
Kevin Hykin <kevin.hykin@bepco.com> wrote:
I just ported from NTO6.0 to 6.1 and my code that was using typeid to
determine object types under 6.0 no longer works. It always evaluates to
false. Is this a known bug?Ex.
std::string temp;
if(typeid(temp) == typeid(std::string))
{
}
The following program works for me. Can you post an example that fails (that didn’t
before)?
#include <stdio.h>
#include
using namespace std;
int main(void)
{
std::string temp;
if ( typeid(temp) == typeid(std::string) ) {
printf(“True\n”);
}
else {
printf(“False\n”);
}
return 0;
}
\
I have had problems under Linux with some versions of gcc, et al and RTTI
functions. Some other versions worked fine.
Bill Caroselli
“Kevin Hykin” <kevin.hykin@bepco.com> wrote in message
news:9meimq$59u$1@inn.qnx.com…
I just ported from NTO6.0 to 6.1 and my code that was using typeid to
determine object types under 6.0 no longer works. It always evaluates to
false. Is this a known bug?Ex.
std::string temp;
if(typeid(temp) == typeid(std::string))
{
}