c programming for interrupts in qnx?

client- server communication - client is sender and server is receiver. when the server receives the data on the ethernet interface(UDP) the kernel in the server is triggered. I am using QNX on the server side. server(i.e embedded pc target) is handling interrupts to trigger the embedded pc target (conatining QNX) to gain the attention to execute the newly arrived data.

I am calculating the time when the interrupt occurs and when it starts scheduling (calculating interrupt latency).

const struct sigevent *handler1(void *area, int id1)
volatile double KernelStartExecutionTime;
struct sigevent *event = (struct sigevent *)area;
KernelStartExecutionTime = GetTimeStamp(); // calculating the time when the kernel //starts executing
measurements[18] = KernelStartExecutionTime ;
//return (NULL);
return event;


/*kernel calls attach the interrupt function handler to the hardware interrupt specified by intr(i.e irq) */
// InterruptAttach() : Attach an interrupt handler to an interrupt source
// interrupt source is handler1 for this example
void ISR(void) //void *ISR (void arg)
the software must tell the OS that it wishes to associate the ISR with a particular source of interrupts.

  • On x86 platforms, there are generally 16 hardware Interrupt Request lines (IRQs) */
    volatile int irq = 0; //0 : A clock that runs at the resolution set by ClockPeriod()
    struct sigevent event;
    event.sigev_notify = SIGEV_INTR;

ThreadCtl (_NTO_TCTL_IO, NULL); // enables the hardware interrupt
id1 = InterruptAttach(irq, &handler1, &event, sizeof(event), 0); // handler1 is the ISR


InterruptWait( 0, NULL );
InterruptUnmask(irq, id1);


InterruptDetach( id1);

int main(int argc, char *argv[])
CreateSocket(); // socket receiving the data from client

 ISR();      //function call for ISR

 return 0;


my question : Is this the right way to create a ISR in qnx ?? how to check the above code is working fine ?? someone please help me ??